7[4-(3-5x)]+5x=5(8x+2)-3

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Solution for 7[4-(3-5x)]+5x=5(8x+2)-3 equation:


Simplifying
7[4 + -1(3 + -5x)] + 5x = 5(8x + 2) + -3
7[4 + (3 * -1 + -5x * -1)] + 5x = 5(8x + 2) + -3
7[4 + (-3 + 5x)] + 5x = 5(8x + 2) + -3

Combine like terms: 4 + -3 = 1
7[1 + 5x] + 5x = 5(8x + 2) + -3
[1 * 7 + 5x * 7] + 5x = 5(8x + 2) + -3
[7 + 35x] + 5x = 5(8x + 2) + -3

Combine like terms: 35x + 5x = 40x
7 + 40x = 5(8x + 2) + -3

Reorder the terms:
7 + 40x = 5(2 + 8x) + -3
7 + 40x = (2 * 5 + 8x * 5) + -3
7 + 40x = (10 + 40x) + -3

Reorder the terms:
7 + 40x = 10 + -3 + 40x

Combine like terms: 10 + -3 = 7
7 + 40x = 7 + 40x

Add '-7' to each side of the equation.
7 + -7 + 40x = 7 + -7 + 40x

Combine like terms: 7 + -7 = 0
0 + 40x = 7 + -7 + 40x
40x = 7 + -7 + 40x

Combine like terms: 7 + -7 = 0
40x = 0 + 40x
40x = 40x

Add '-40x' to each side of the equation.
40x + -40x = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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